What is the integral from-3 to 4 of 1/x ?

The integral from-3 to 4 of 1/x is diverges

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integral from-3 to 4 of 1/x

\int_{- 3}^{4} \frac{1}{x} d x

diverges

Solution steps

\int_{- 3}^{4} \frac{1}{x} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 3}^{0} \frac{1}{x} d x + \int_{0}^{4} \frac{1}{x} d x

\int_{- 3}^{0} \frac{1}{x} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

11 y^{^{''}} + 12 y^{^{'}} + 96 y = 5 cos (4 t)

\frac{\partial}{\partial y} (x^{2} sin (4 y))

\frac{\partial}{\partial z} (ln (x^{2} + y^{2}) - z)

n = 0 \sum \infty 2 n + 1

\int 39 sec^{4} (x) d x

What is the integral from-3 to 4 of 1/x ?
The integral from-3 to 4 of 1/x is diverges