What is the derivative of x^3-3x+1 ?

The derivative of x^3-3x+1 is 3x^2-3

What is the first derivative of x^3-3x+1 ?

The first derivative of x^3-3x+1 is 3x^2-3

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derivative of

x^{3} - 3 x + 1

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

\int \frac{3 x ^{2}}{x ^{3} + 7} d x

\frac{\partial}{\partial x} (ln (cos (x)))

\frac{( x ^{2} )}{x ^{2} + 27}

\frac{d}{d x} (\frac{cos ( x )}{lo g _{3} ( x )})

\int \frac{x}{4 x ^{2} + 5} d x

What is the derivative of x^3-3x+1 ?
The derivative of x^3-3x+1 is 3x^2-3
What is the first derivative of x^3-3x+1 ?
The first derivative of x^3-3x+1 is 3x^2-3