What is the integral of 1/(\sqrt[9]{x)} ?

The integral of 1/(\sqrt[9]{x)} is 9/8 x^{8/9}+C

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integral of 1/(\sqrt[9]{x)}

\frac{9}{8} x^{\frac{8}{9}} + C

Solution steps

Apply the Power Rule

: \frac{9}{8} x^{\frac{8}{9}}

= \frac{9}{8} x^{\frac{8}{9}}

Add a constant to the solution

= \frac{9}{8} x^{\frac{8}{9}} + C

x = y^{2}, x = y + 2

y^{^{'}} = e^{(3 x + 2 y)}

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What is the integral of 1/(\sqrt[9]{x)} ?
The integral of 1/(\sqrt[9]{x)} is 9/8 x^{8/9}+C