What is (\partial)/(\partial z)(yz^2) ?

The answer to (\partial)/(\partial z)(yz^2) is 2yz

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(\partial)/(\partial z)(yz^2)

\frac{\partial}{\partial z} (y z^{2})

2 yz

Solution steps

\frac{\partial}{\partial z} (y z^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y \cdot 2 z^{2 - 1}

Simplify

= 2 yz

\frac{\partial}{\partial x} (ln (x \cdot y))

X^{\frac{9}{6}}, 8, 5

\int \frac{( 8 x - 3 )}{x ^{2} + x + 1} d x

n = 1 \sum \infty 2^{n} - 3

\frac{d}{d x} (8^{x^{3}})

What is (\partial)/(\partial z)(yz^2) ?
The answer to (\partial)/(\partial z)(yz^2) is 2yz