What is the solution for (dy)/(dt)=4y+y^3 ?

The solution for (dy)/(dt)=4y+y^3 is y= 2/(sqrt(e^{-8t-c_{1))-1}},y=-2/(sqrt(e^{-8t-c_{1))-1}}

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(dy)/(dt)=4y+y^3

\frac{d y}{d t} = 4 y + y^{3}

y = \frac{2}{e ^{- 8 t - c_{1}} - 1}, y = - \frac{2}{e ^{- 8 t - c_{1}} - 1}

Solution steps

\frac{d y}{d t} = 4 y + y^{3}

Solve Bernoulli ODE:

y = \frac{2}{e ^{- 8 t - c_{1}} - 1}, y = - \frac{2}{e ^{- 8 t - c_{1}} - 1}

y = \frac{2}{e ^{- 8 t - c_{1}} - 1}, y = - \frac{2}{e ^{- 8 t - c_{1}} - 1}

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What is the solution for (dy)/(dt)=4y+y^3 ?
The solution for (dy)/(dt)=4y+y^3 is y= 2/(sqrt(e^{-8t-c_{1))-1}},y=-2/(sqrt(e^{-8t-c_{1))-1}}