What is the limit as x approaches 1 of 9/(x^3-1) ?

The limit as x approaches 1 of 9/(x^3-1) is diverges

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limit as x approaches 1 of 9/(x^3-1)

x \to 1 lim (\frac{9}{x ^{3} - 1})

diverges

Solution steps

x \to 1 lim (\frac{9}{x ^{3} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{9}{x ^{3} - 1}) = \infty

x \to 1 - lim (\frac{9}{x ^{3} - 1}) = - \infty

= diverges

y = 7 arctan (x - 1 + x^{2})

\int_{0}^{3} 2 π x (3 x - x^{2}) d x

\frac{\partial}{\partial x} (cos (5 x + 9 y + 4 z))

y^{^{'}} = y - y^{2}, y (0) = 10

\frac{d}{d x} (2 x^{\frac{9}{2}})

What is the limit as x approaches 1 of 9/(x^3-1) ?
The limit as x approaches 1 of 9/(x^3-1) is diverges