What is the (x+sqrt(x))^' ?

The (x+sqrt(x))^' is 1+1/(2sqrt(x))

What is the first (x+sqrt(x))^' ?

The first (x+sqrt(x))^' is 1+1/(2sqrt(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + x)^{^{'}}

1 + \frac{1}{2 x}

Solution steps

(x + x)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x^{^{'}} + (x)^{^{'}}

x^{'} = 1

(x)^{'} = \frac{1}{2 x}

= 1 + \frac{1}{2 x}

\int \frac{8}{( x - 2 ) ^{2}} d x

7 x (x + y) y^{^{'}} = 7 y (x - y)

\frac{\partial}{\partial x} (8 x^{0.5} y^{0.5})

\frac{d}{d x} (- \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}})

f (x) = x^{3} - 4 x + 6, (2, 6)