What is the integral of sin(θ)cos(θ) ?

The integral of sin(θ)cos(θ) is (sin^2(θ))/2+C

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integral of sin(θ)cos(θ)

\int sin (θ) cos (θ) d θ

\frac{sin ^{2} ( θ )}{2} + C

Solution steps

\int sin (θ) cos (θ) d θ

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (θ)

= \frac{sin ^{2} ( θ )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( θ )}{2} + C

\int + sin^{2} (4 x) cos^{2} (4 x) d x

8 x^{4} - 1 x^{2} + 9 x + 2, x = 0.05

x \to 1 lim (\frac{x ^{2} - 1}{2 x + 1 - 3})

2 lo g_{5} (t)

(y - x 5) d x + (x + y 5) d y = 0

What is the integral of sin(θ)cos(θ) ?
The integral of sin(θ)cos(θ) is (sin^2(θ))/2+C