What is the integral of sin^2(θ)cos(θ) ?

The integral of sin^2(θ)cos(θ) is (sin^3(θ))/3+C

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integral of sin^2(θ)cos(θ)

\int sin^{2} (θ) cos (θ) d θ

\frac{sin ^{3} ( θ )}{3} + C

Solution steps

\int sin^{2} (θ) cos (θ) d θ

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = sin (θ)

= \frac{sin ^{3} ( θ )}{3}

Add a constant to the solution

= \frac{sin ^{3} ( θ )}{3} + C

\int \frac{( 3 x - 2 ) ^{2} + ( 3 x + 2 ) ^{2}}{x ^{2}} d x

\frac{cos ( 2 x )}{sin ( 2 x )}

\int (4 x^{5} + 3 x + 8) d x

f^{^{'}} (x) = 8 x^{3} - 6 x^{2} + 10 x - 9, f (1) = 24

1 - x^{2}

What is the integral of sin^2(θ)cos(θ) ?
The integral of sin^2(θ)cos(θ) is (sin^3(θ))/3+C