What is the derivative of y=(sqrt(x))/(7+x) ?

The derivative of y=(sqrt(x))/(7+x) is (7-x)/(2sqrt(x)(7+x)^2)

What is the first derivative of y=(sqrt(x))/(7+x) ?

The first derivative of y=(sqrt(x))/(7+x) is (7-x)/(2sqrt(x)(7+x)^2)

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derivative of

y = \frac{x}{7 + x}

\frac{7 - x}{2 x ( 7 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{7 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ) ( 7 + x ) - \frac{d}{d x} ( 7 + x ) x}{( 7 + x ) ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (7 + x) = 1

= \frac{\frac{1}{2 x} ( 7 + x ) - 1 \cdot x}{( 7 + x ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( 7 + x ) - 1 \cdot x}{( 7 + x ) ^{2}} : \frac{7 - x}{2 x ( 7 + x ) ^{2}}

= \frac{7 - x}{2 x ( 7 + x ) ^{2}}

x \to 1 lim (7 x + 42)

\frac{d}{d x} (5^{m x})

\int 4 - x d x

x \to - 10 lim (\frac{1}{x + 10})

x \to 0 - lim (e^{x})

What is the derivative of y=(sqrt(x))/(7+x) ?
The derivative of y=(sqrt(x))/(7+x) is (7-x)/(2sqrt(x)(7+x)^2)
What is the first derivative of y=(sqrt(x))/(7+x) ?
The first derivative of y=(sqrt(x))/(7+x) is (7-x)/(2sqrt(x)(7+x)^2)