What is the solution for 3x+y-2+(dy)/(dx)(x-1)=0 ?

The solution for 3x+y-2+(dy)/(dx)(x-1)=0 is y=-(3x^2)/(2(x-1))+(2x)/(x-1)+(c_{1})/(x-1)

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3x+y-2+(dy)/(dx)(x-1)=0

3 x + y - 2 + \frac{d y}{d x} (x - 1) = 0

y = - \frac{3 x ^{2}}{2 ( x - 1 )} + \frac{2 x}{x - 1} + \frac{c _{1}}{x - 1}

Solution steps

3 x + y - 2 + \frac{d y}{d x} (x - 1) = 0

Solve linear ODE:

y = - \frac{3 x ^{2}}{2 ( x - 1 )} + \frac{2 x}{x - 1} + \frac{c _{1}}{x - 1}

y = - \frac{3 x ^{2}}{2 ( x - 1 )} + \frac{2 x}{x - 1} + \frac{c _{1}}{x - 1}

n = 0 \sum \infty \frac{1}{2 n + 1}

\int \frac{1}{1 + 4 x ^{2} + 4 x ^{4}} d x

x \to \frac{π}{4} lim (2 sin (3 x))

\frac{d}{d x} ((1 - x^{4})^{3})

\int 6 x + 4 d x

What is the solution for 3x+y-2+(dy)/(dx)(x-1)=0 ?
The solution for 3x+y-2+(dy)/(dx)(x-1)=0 is y=-(3x^2)/(2(x-1))+(2x)/(x-1)+(c_{1})/(x-1)