What is the derivative of y=sin(9x)+cos(7x) ?

The derivative of y=sin(9x)+cos(7x) is cos(9x)*9-sin(7x)*7

What is the first derivative of y=sin(9x)+cos(7x) ?

The first derivative of y=sin(9x)+cos(7x) is cos(9x)*9-sin(7x)*7

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derivative of

y = sin (9 x) + cos (7 x)

cos (9 x) \cdot 9 - sin (7 x) \cdot 7

Solution steps

\frac{d}{d x} (sin (9 x) + cos (7 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (9 x)) + \frac{d}{d x} (cos (7 x))

\frac{d}{d x} (sin (9 x)) = cos (9 x) \cdot 9

\frac{d}{d x} (cos (7 x)) = - sin (7 x) \cdot 7

= cos (9 x) \cdot 9 - sin (7 x) \cdot 7

\frac{d}{d x} (2 - 5 x^{2})

\int_{2}^{3} \frac{1}{3 x - 2} d x

f (x) = x^{e}

x \to 0 lim (\frac{tan ( 6 x )}{x})

f (x) = 3 e^{x} x

What is the derivative of y=sin(9x)+cos(7x) ?
The derivative of y=sin(9x)+cos(7x) is cos(9x)*9-sin(7x)*7
What is the first derivative of y=sin(9x)+cos(7x) ?
The first derivative of y=sin(9x)+cos(7x) is cos(9x)*9-sin(7x)*7