What is the derivative of-3x^4+4x^3+2 ?

The derivative of-3x^4+4x^3+2 is -12x^3+12x^2

What is the first derivative of-3x^4+4x^3+2 ?

The first derivative of-3x^4+4x^3+2 is -12x^3+12x^2

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\frac{d}{d x} (- 3 x^{4} + 4 x^{3} + 2)

- 12 x^{3} + 12 x^{2}

Solution steps

\frac{d}{d x} (- 3 x^{4} + 4 x^{3} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (2) = 0

= - 12 x^{3} + 12 x^{2} + 0

Simplify

= - 12 x^{3} + 12 x^{2}

\int 3 e^{- s t} d t

\int - 3 cos (5 x) d x

f (x) = 16 x^{\frac{1}{8}}

y^{^{''}} - 4 y^{^{'}} + 4 y = (12 x^{2} - 6 x) e^{2 x}

\int \frac{( 12 x + 30 )}{x ^{2} + 2 x - 8} d x

What is the derivative of-3x^4+4x^3+2 ?
The derivative of-3x^4+4x^3+2 is -12x^3+12x^2
What is the first derivative of-3x^4+4x^3+2 ?
The first derivative of-3x^4+4x^3+2 is -12x^3+12x^2