What is the first derivative of 4x-5 ?

The first derivative of 4x-5 is 4

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derivative of 4x-5

\frac{d}{d x} (4 x - 5)

4

Solution steps

\frac{d}{d x} (4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 4 - 0

Simplify

= 4

x^{2} + 2 x, 1

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 4 y)

x \to \infty lim ((1 + \frac{2}{x + 1})^{x + 1})

n = 0 \sum \infty n^{- 0.48}

x \to 1 lim ([f (x) + g (x)])