What is the derivative of 4^{2x} ?

The derivative of 4^{2x} is ln(2)*2^{4x+2}

What is the first derivative of 4^{2x} ?

The first derivative of 4^{2x} is ln(2)*2^{4x+2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (4^{2 x})

ln (2) \cdot 2^{4 x + 2}

Solution steps

\frac{d}{d x} (4^{2 x})

Simplify

4^{2 x} : 1 6^{x}

= \frac{d}{d x} (1 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 1 6^{x} ln (16)

Simplify

1 6^{x} ln (16) : ln (2) \cdot 2^{4 x + 2}

= ln (2) \cdot 2^{4 x + 2}

f (x) = \frac{8 x ^{2} + 8 x + 2}{x}

\frac{( s )}{( s - 1 ) ^{2}}

\int x^{2} sin (2 x) d x

\frac{d}{d x} ((a x^{2} + b x + c) e^{\frac{- x}{6}})

x \to 7 lim (\frac{5 x}{x + 2})

What is the derivative of 4^{2x} ?
The derivative of 4^{2x} is ln(2)*2^{4x+2}
What is the first derivative of 4^{2x} ?
The first derivative of 4^{2x} is ln(2)*2^{4x+2}