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Popular >

y^'=2(1+y^2)x

Solution

y^{^{'}} = 2 (1 + y^{2}) x

Solution

y = tan (x^{2} + c_{1})

Solution steps

y^{'} (x) = 2 (1 + y^{2}) x

Solve separable ODE:

y = tan (x^{2} + c_{1})

y = tan (x^{2} + c_{1})

Popular Examples

derivative of 2x-1-1/x

\frac{d}{d x} (2 x - 1 - \frac{1}{x})

integral of 1/((1-x^2)^{1/2)}

\int \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

(\partial)/(\partial x)(e^{-x/y}+ln(y/x))

\frac{\partial}{\partial x} (e^{- \frac{x}{y}} + ln (\frac{y}{x}))

integral of (4x)/(2x^2+3)

\int \frac{4 x}{2 x ^{2} + 3} d x

integral of 7/(x^2+4)

\int \frac{7}{x ^{2} + 4} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2(1+y^2)x ?
The solution for y^'=2(1+y^2)x is y=tan(x^2+c_{1})