What is the derivative of (2x+|x|/(1+|x|)) ?

The derivative of (2x+|x|/(1+|x|)) is (x+2|x|)/(|x|(1+|x|)^2)

What is the first derivative of (2x+|x|/(1+|x|)) ?

The first derivative of (2x+|x|/(1+|x|)) is (x+2|x|)/(|x|(1+|x|)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{2 x + ∣ x ∣}{1 + ∣ x ∣})

\frac{x + 2 ∣ x ∣}{∣ x ∣ ( 1 + ∣ x ∣ ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x + ∣ x ∣}{1 + ∣ x ∣})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + ∣ x ∣ ) ( 1 + ∣ x ∣ ) - \frac{d}{d x} ( 1 + ∣ x ∣ ) ( 2 x + ∣ x ∣ )}{( 1 + ∣ x ∣ ) ^{2}}

\frac{d}{d x} (2 x + ∣ x ∣) = 2 + \frac{x}{∣ x ∣}

\frac{d}{d x} (1 + ∣ x ∣) = \frac{x}{∣ x ∣}

= \frac{( 2 + \frac{x}{∣ x ∣} ) ( 1 + ∣ x ∣ ) - \frac{x}{∣ x ∣} ( 2 x + ∣ x ∣ )}{( 1 + ∣ x ∣ ) ^{2}}

Simplify

\frac{( 2 + \frac{x}{∣ x ∣} ) ( 1 + ∣ x ∣ ) - \frac{x}{∣ x ∣} ( 2 x + ∣ x ∣ )}{( 1 + ∣ x ∣ ) ^{2}} : \frac{x + 2 ∣ x ∣}{∣ x ∣ ( 1 + ∣ x ∣ ) ^{2}}

= \frac{x + 2 ∣ x ∣}{∣ x ∣ ( 1 + ∣ x ∣ ) ^{2}}

\int \frac{9 x ^{2} - 8 x + 20}{x ^{3} + 4 x} d x

\frac{75 x}{x ^{2} + 100}

1 - 2 x

\frac{d}{d x} (\frac{x}{2 ( x ^{2} - 1 ) ^{2} - 1})^{2}

y^{^{''}} - 9 y = 0, y (0) = 6

What is the derivative of (2x+|x|/(1+|x|)) ?
The derivative of (2x+|x|/(1+|x|)) is (x+2|x|)/(|x|(1+|x|)^2)
What is the first derivative of (2x+|x|/(1+|x|)) ?
The first derivative of (2x+|x|/(1+|x|)) is (x+2|x|)/(|x|(1+|x|)^2)