What is (\partial)/(\partial x)(x^2*ln(y)) ?

The answer to (\partial)/(\partial x)(x^2*ln(y)) is 2xln(y)

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(\partial)/(\partial x)(x^2*ln(y))

\frac{\partial}{\partial x} (x^{2} \cdot ln (y))

2 x ln (y)

Solution steps

\frac{\partial}{\partial x} (x^{2} ln (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (y) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= ln (y) \cdot 2 x^{2 - 1}

Simplify

= 2 x ln (y)

\frac{d}{d x} (sin (2 x - \frac{π}{3}))

\frac{\partial}{\partial x} (x^{3} + y^{2} - y x^{2} - x y)

\frac{d}{d t} (5 e^{t} cos (t))

f (x) = cos (5 x)

12 x^{3} - 3 y x^{4} + 1 y^{^{'}} = 0

What is (\partial)/(\partial x)(x^2*ln(y)) ?
The answer to (\partial)/(\partial x)(x^2*ln(y)) is 2xln(y)