What is the tangent of y=5x-2sqrt(x),(1,3) ?

The tangent of y=5x-2sqrt(x),(1,3) is y=4x-1

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tangent of y=5x-2sqrt(x),(1,3)

tangent of

y = 5 x - 2 x, (1, 3)

y = 4 x - 1

Solution steps

Find the slope of

y = 5 x - 2 x : \frac{d y}{d x} = 5 - \frac{1}{x}

Compute the slope of

y = 5 x - 2 x

(1, 3) : m = 4

Find the line with slope m=

4

and passing through

(1, 3) : y = 4 x - 1

y = 4 x - 1

x \to 0 lim (sin (x) - 2 x)

\int 8 x y

y = (1 + 5 x)^{8}, (0, 1)

\frac{d}{d x} (n ln (0.4 n x + 0.6))

\frac{( x ^{2} )}{8 + x}

What is the tangent of y=5x-2sqrt(x),(1,3) ?
The tangent of y=5x-2sqrt(x),(1,3) is y=4x-1