What is the solution for t^2y^{''}+17ty^'+64y=0 ?

The solution for t^2y^{''}+17ty^'+64y=0 is y=(c_{1})/(t^8)+(c_{2}ln(t))/(t^8)

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t^2y^{''}+17ty^'+64y=0

t^{2} y^{^{''}} + 17 t y^{^{'}} + 64 y = 0

y = \frac{c _{1}}{t ^{8}} + \frac{c _{2} ln ( t )}{t ^{8}}

Solution steps

t^{2} y^{''} (t) + 17 t y^{'} (t) + 64 y = 0

Solve linear ODE:

y = \frac{c _{1}}{t ^{8}} + \frac{c _{2} ln ( t )}{t ^{8}}

y = \frac{c _{1}}{t ^{8}} + \frac{c _{2} ln ( t )}{t ^{8}}

x \to 0 lim (x (0))

\frac{\partial}{\partial y} (sin (- 2 x) cos (6 y))

y^{^{''}} + 12 y^{^{'}} + 36 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\frac{d}{d x} (tan (e^{π}))

\frac{d}{d x} (\frac{1}{2 x + 6})

What is the solution for t^2y^{''}+17ty^'+64y=0 ?
The solution for t^2y^{''}+17ty^'+64y=0 is y=(c_{1})/(t^8)+(c_{2}ln(t))/(t^8)