What is (\partial)/(\partial x)(sin(5pix+4y)) ?

The answer to (\partial)/(\partial x)(sin(5pix+4y)) is cos(5pix+4y)*5pi

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(\partial)/(\partial x)(sin(5pix+4y))

\frac{\partial}{\partial x} (sin (5 π x + 4 y))

cos (5 π x + 4 y) \cdot 5 π

Solution steps

\frac{\partial}{\partial x} (sin (5 π x + 4 y))

Treat

y

as a constant

Apply the chain rule:

cos (5 π x + 4 y) \frac{\partial}{\partial x} (5 π x + 4 y)

= cos (5 π x + 4 y) \frac{\partial}{\partial x} (5 π x + 4 y)

\frac{\partial}{\partial x} (5 π x + 4 y) = 5 π

= cos (5 π x + 4 y) \cdot 5 π

\frac{d}{d x} ((\frac{1}{e ^{x}})^{100})

\int \frac{e ^{x}}{( e ^{x} + 1 ) ln ( e ^{x} + 1 )} d x

y = ln (x^{2}), at x = 3

\int sinh^{2} (x) d x

\int_{0}^{4} x (x + 2) d x

What is (\partial)/(\partial x)(sin(5pix+4y)) ?
The answer to (\partial)/(\partial x)(sin(5pix+4y)) is cos(5pix+4y)*5pi