What is the sum from n=1 to infinity of (3^n)/(n^3) ?

The sum from n=1 to infinity of (3^n)/(n^3) is diverges

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sum from n=1 to infinity of (3^n)/(n^3)

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

diverges

Solution steps

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

Apply Series Ratio Test:

diverges

= diverges

\int \frac{sin ( 2 x )}{( 1 + cos ( 2 x ) ) ^{3}} d x

f (x) = \frac{x ^{5}}{5} + \frac{1}{12 x ^{3}}

y = sin (2 x) + sin (2) (2 x)

x \to - \frac{π}{2} lim (2 tan (x))

\frac{d}{d x} (\frac{e ^{x + 1}}{x ^{2} + 1})

What is the sum from n=1 to infinity of (3^n)/(n^3) ?
The sum from n=1 to infinity of (3^n)/(n^3) is diverges