What is (\partial)/(\partial x)(3x^2-4xy) ?

The answer to (\partial)/(\partial x)(3x^2-4xy) is 6x-4y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(3x^2-4xy)

\frac{\partial}{\partial x} (3 x^{2} - 4 x y)

6 x - 4 y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 4 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (4 x y) = 4 y

= 6 x - 4 y

f (x) = (x^{2} + 2)^{2}, (0, 4)

x \to 2 lim (\frac{x ^{2} - 4}{x + 4})

\int (3 x - 2) e^{- x} d x

\int 125

f (x) = x^{3} - 12 x + 2

What is (\partial)/(\partial x)(3x^2-4xy) ?
The answer to (\partial)/(\partial x)(3x^2-4xy) is 6x-4y