What is the tangent of x^2+y^2=25,(3,-4) ?

The tangent of x^2+y^2=25,(3,-4) is y= 3/4 x-25/4

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tangent of x^2+y^2=25,(3,-4)

tangent of

x^{2} + y^{2} = 25, (3, - 4)

y = \frac{3}{4} x - \frac{25}{4}

Solution steps

Find the slope of

x^{2} + y^{2} = 25 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 25

(3, - 4) : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(3, - 4) : y = \frac{3}{4} x - \frac{25}{4}

y = \frac{3}{4} x - \frac{25}{4}

2 x e^{- 2 x} - 3 e^{x^{3}}

\frac{\partial}{\partial x} (3 x sin (y))

\frac{\partial}{\partial y} (7 x^{\frac{y}{z}})

y^{^{'}} + \frac{2 y}{x} = \frac{2}{x}

\int \frac{u}{u + 1} d u

What is the tangent of x^2+y^2=25,(3,-4) ?
The tangent of x^2+y^2=25,(3,-4) is y= 3/4 x-25/4