What is the derivative of 2/(x^3+c) ?

The derivative of 2/(x^3+c) is -6/(x^4)

What is the first derivative of 2/(x^3+c) ?

The first derivative of 2/(x^3+c) is -6/(x^4)

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\frac{d}{d x} (\frac{2}{x ^{3}} + c)

- \frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{3}} + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x ^{3}}) + \frac{d c}{d x}

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

\frac{d c}{d x} = 0

= - \frac{6}{x ^{4}} + 0

Simplify

= - \frac{6}{x ^{4}}

\int_{3}^{6} \frac{1}{( 4 - x ) ^{2}} d x

\frac{s ^{2} + 3}{2 s ^{2} + 5}

\frac{d}{d x} ((\frac{3}{4})^{\frac{- 4}{3}})

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + y ^{2} + 1})

What is the derivative of 2/(x^3+c) ?
The derivative of 2/(x^3+c) is -6/(x^4)
What is the first derivative of 2/(x^3+c) ?
The first derivative of 2/(x^3+c) is -6/(x^4)