What is the integral of (ln(17x))/x ?

The integral of (ln(17x))/x is (ln^2(17x))/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (ln(17x))/x

\int \frac{ln ( 17 x )}{x} d x

\frac{ln ^{2} ( 17 x )}{2} + C

Solution steps

\int \frac{ln ( 17 x )}{x} d x

Apply u-substitution

: \int \frac{ln ( u )}{u} d u

= \int \frac{ln ( u )}{u} d u

Apply u-substitution

: \int v d v

= \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= \frac{v ^{2}}{2}

Substitute back

= \frac{ln ^{2} ( 17 x )}{2}

Add a constant to the solution

= \frac{ln ^{2} ( 17 x )}{2} + C

\frac{\partial}{\partial x} ((\frac{x}{2})^{2})

\int_{0}^{1} ln (x) d x

\frac{d}{d x} (\frac{2 x}{7 - tan ( x )})

\int_{a}^{2 a} a - \frac{a ^{3}}{x ^{2}} d x

7 ln (sec (x) + tan (x))

What is the integral of (ln(17x))/x ?
The integral of (ln(17x))/x is (ln^2(17x))/2+C