What is (\partial)/(\partial x)(-2cos(x)) ?

The answer to (\partial)/(\partial x)(-2cos(x)) is 2sin(x)

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(\partial)/(\partial x)(-2cos(x))

\frac{\partial}{\partial x} (- 2 cos (x))

2 sin (x)

Solution steps

\frac{\partial}{\partial x} (- 2 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= - 2 (- sin (x))

Simplify

= 2 sin (x)

\int 2 arctan (5 y) d y

x \to 0 lim (sin (5 x))

\frac{d}{d x} (\frac{( x + 1 ) ( x - 2 )}{( x - 1 ) ( x + 2 )})

f (x) = e^{x - 1} - 1

y^{^{'}} - 3 y = \frac{y}{x}

What is (\partial)/(\partial x)(-2cos(x)) ?
The answer to (\partial)/(\partial x)(-2cos(x)) is 2sin(x)