What is (\partial)/(\partial x)(-2e^xln(y)) ?

The answer to (\partial)/(\partial x)(-2e^xln(y)) is -2ln(y)e^x

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(\partial)/(\partial x)(-2e^xln(y))

\frac{\partial}{\partial x} (- 2 e^{x} ln (y))

- 2 ln (y) e^{x}

Solution steps

\frac{\partial}{\partial x} (- 2 e^{x} ln (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 ln (y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - 2 ln (y) e^{x}

\int (\frac{6}{5 x ^{2}} - 1) d x

\int \frac{1}{( x ^{2} + 8 x + 17 ) ^{2}} d x

x \to 0 lim ((1 + 6 x)^{\frac{4}{x}})

\frac{\partial}{\partial x} (e^{3 x^{2} + y} (x - y))

y^{^{''}} - 2 y^{^{'}} + y = x e^{x} + 4

What is (\partial)/(\partial x)(-2e^xln(y)) ?
The answer to (\partial)/(\partial x)(-2e^xln(y)) is -2ln(y)e^x