What is the derivative of 2e^x+4/(\sqrt[3]{x}) ?

The derivative of 2e^x+4/(\sqrt[3]{x}) is 2e^x-4/(3x^{4/3)}

What is the first derivative of 2e^x+4/(\sqrt[3]{x}) ?

The first derivative of 2e^x+4/(\sqrt[3]{x}) is 2e^x-4/(3x^{4/3)}

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2 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= 2 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

x \to - 3 + lim (\frac{4 x + 3}{x + 3})

\frac{d y}{d x} = 2 x y^{\frac{1}{2}}

4 - x^{2}, 16 - 7 x

\int (9 - x) x d x

\frac{\partial}{\partial x} (x \cdot e^{(- y)})

What is the derivative of 2e^x+4/(\sqrt[3]{x}) ?
The derivative of 2e^x+4/(\sqrt[3]{x}) is 2e^x-4/(3x^{4/3)}
What is the first derivative of 2e^x+4/(\sqrt[3]{x}) ?
The first derivative of 2e^x+4/(\sqrt[3]{x}) is 2e^x-4/(3x^{4/3)}