What is the integral of (sec^2(sqrt(x)))/(sqrt(x)) ?

The integral of (sec^2(sqrt(x)))/(sqrt(x)) is 2tan(sqrt(x))+C

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integral of (sec^2(sqrt(x)))/(sqrt(x))

\int \frac{sec ^{2} ( x )}{x} d x

2 tan (x) + C

Solution steps

\int \frac{sec ^{2} ( x )}{x} d x

Rewrite using trig identities

= \int \frac{1 + tan ^{2} ( x )}{x} d x

Expand

\frac{1 + tan ^{2} ( x )}{x} : \frac{1}{x} + \frac{tan ^{2} ( x )}{x}

= \int \frac{1}{x} + \frac{tan ^{2} ( x )}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int \frac{tan ^{2} ( x )}{x} d x

\int \frac{1}{x} d x = 2 x

\int \frac{tan ^{2} ( x )}{x} d x = - 2 x + 2 tan (x)

= 2 x - 2 x + 2 tan (x)

Simplify

= 2 tan (x)

Add a constant to the solution

= 2 tan (x) + C

\int cos (nπ x) d x

\frac{d}{d x} (arccos (\frac{1 - x ^{2}}{1 + x ^{2}}))

x (x - 1)

y^{^{'}} = (x + 1)^{2}

f (x) = 3 x^{3} - 3 x, (1, 0)

What is the integral of (sec^2(sqrt(x)))/(sqrt(x)) ?
The integral of (sec^2(sqrt(x)))/(sqrt(x)) is 2tan(sqrt(x))+C