What is the derivative of log_{9}(ln(x)) ?

The derivative of log_{9}(ln(x)) is 1/(2ln(3)xln(x))

What is the first derivative of log_{9}(ln(x)) ?

The first derivative of log_{9}(ln(x)) is 1/(2ln(3)xln(x))

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derivative of

lo g_{9} (ln (x))

\frac{1}{2 ln ( 3 ) x ln ( x )}

Solution steps

\frac{d}{d x} (lo g_{9} (ln (x)))

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

= \frac{d}{d x} (\frac{ln ( ln ( x ) )}{ln ( 9 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 9 )} \frac{d}{d x} (ln (ln (x)))

Apply the chain rule:

\frac{1}{ln ( x )} \frac{d}{d x} (ln (x))

= \frac{1}{ln ( x )} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= \frac{1}{ln ( 9 )} \cdot \frac{1}{ln ( x )} \cdot \frac{1}{x}

Simplify

\frac{1}{ln ( 9 )} \cdot \frac{1}{ln ( x )} \cdot \frac{1}{x} : \frac{1}{2 ln ( 3 ) x ln ( x )}

= \frac{1}{2 ln ( 3 ) x ln ( x )}

\frac{d}{d x} (1 - 4 x)

x \to + 0 lim (\frac{8}{6 + e ^{x}})

\int_{1}^{\infty} \frac{3}{x ^{4}} d x

\frac{( 17 - x ) 2 x + 8}{2}

x \to - 1 lim (x^{4} - 2 x^{2} - 1)

What is the derivative of log_{9}(ln(x)) ?
The derivative of log_{9}(ln(x)) is 1/(2ln(3)xln(x))
What is the first derivative of log_{9}(ln(x)) ?
The first derivative of log_{9}(ln(x)) is 1/(2ln(3)xln(x))