What is the integral of \sqrt[3]{x}+1/(\sqrt[3]{x)} ?

The integral of \sqrt[3]{x}+1/(\sqrt[3]{x)} is 3/4 x^{4/3}+3/2 x^{2/3}+C

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integral of \sqrt[3]{x}+1/(\sqrt[3]{x)}

\frac{3}{4} x^{\frac{4}{3}} + \frac{3}{2} x^{\frac{2}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{3}{4} x^{\frac{4}{3}} + \frac{3}{2} x^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + \frac{3}{2} x^{\frac{2}{3}} + C

\frac{s}{( s + 1 )}

\frac{\partial}{\partial z} (x^{yz})

\frac{d}{d x} (11 arccot (x) + 11 arccot (\frac{1}{x}))

\frac{- 5}{( 2 x ^{3} + 7 ) ^{2}}

(2, 7), (- 5, 2)

What is the integral of \sqrt[3]{x}+1/(\sqrt[3]{x)} ?
The integral of \sqrt[3]{x}+1/(\sqrt[3]{x)} is 3/4 x^{4/3}+3/2 x^{2/3}+C