What is the derivative of (x^2)/(8+x) ?

The derivative of (x^2)/(8+x) is (16x+x^2)/((8+x)^2)

What is the first derivative of (x^2)/(8+x) ?

The first derivative of (x^2)/(8+x) is (16x+x^2)/((8+x)^2)

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derivative of

\frac{x ^{2}}{8 + x}

\frac{16 x + x ^{2}}{( 8 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{8 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 8 + x ) - \frac{d}{d x} ( 8 + x ) x ^{2}}{( 8 + x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 + x) = 1

= \frac{2 x ( 8 + x ) - 1 \cdot x ^{2}}{( 8 + x ) ^{2}}

Simplify

\frac{2 x ( 8 + x ) - 1 \cdot x ^{2}}{( 8 + x ) ^{2}} : \frac{16 x + x ^{2}}{( 8 + x ) ^{2}}

= \frac{16 x + x ^{2}}{( 8 + x ) ^{2}}

\int_{0}^{1} 23 cos (x^{2}) d x

\frac{d}{d x} ((tan (x))^{\frac{1}{x}})

\int \frac{1}{x ^{2} + 5 x - 6} d x

\frac{d}{d x} (2 c x)

\int \frac{1}{x ( ln ( x ^{4} ) ) ^{9}} d x

What is the derivative of (x^2)/(8+x) ?
The derivative of (x^2)/(8+x) is (16x+x^2)/((8+x)^2)
What is the first derivative of (x^2)/(8+x) ?
The first derivative of (x^2)/(8+x) is (16x+x^2)/((8+x)^2)