What is the derivative of cos(2x^3-3x) ?

The derivative of cos(2x^3-3x) is -sin(2x^3-3x)(6x^2-3)

What is the first derivative of cos(2x^3-3x) ?

The first derivative of cos(2x^3-3x) is -sin(2x^3-3x)(6x^2-3)

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\frac{d}{d x} (cos (2 x^{3} - 3 x))

- sin (2 x^{3} - 3 x) (6 x^{2} - 3)

Solution steps

\frac{d}{d x} (cos (2 x^{3} - 3 x))

Apply the chain rule:

- sin (2 x^{3} - 3 x) \frac{d}{d x} (2 x^{3} - 3 x)

= - sin (2 x^{3} - 3 x) \frac{d}{d x} (2 x^{3} - 3 x)

\frac{d}{d x} (2 x^{3} - 3 x) = 6 x^{2} - 3

= - sin (2 x^{3} - 3 x) (6 x^{2} - 3)

f (x) = (\frac{5 ^{3 x^{7}}}{8 x ^{2}})^{4}

\int \frac{x - 3}{x ^{2} - 12 x + 36} d x

n = 1 \sum \infty \frac{n}{n + 3}

f (x) = (2 + 4 x) (5 - 4 x), at x = 1

y = 2 x^{3} - 2 x^{2} - 2 x

What is the derivative of cos(2x^3-3x) ?
The derivative of cos(2x^3-3x) is -sin(2x^3-3x)(6x^2-3)
What is the first derivative of cos(2x^3-3x) ?
The first derivative of cos(2x^3-3x) is -sin(2x^3-3x)(6x^2-3)