What is the derivative of 7cos(4x) ?

The derivative of 7cos(4x) is -28sin(4x)

What is the first derivative of 7cos(4x) ?

The first derivative of 7cos(4x) is -28sin(4x)

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derivative of

7 cos (4 x)

- 28 sin (4 x)

Solution steps

\frac{d}{d x} (7 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 7 (- sin (4 x) \cdot 4)

Simplify

= - 28 sin (4 x)

- 2 y^{^{''}} + 4 y^{^{'}} + 3 y = 1

f (x) = (x^{2} + 2) (x^{4} + 1)

cos (t) y^{^{'}} - sin (t) y = t^{2}

\frac{x}{x + \frac{c}{x}}

7 x + 6 x

What is the derivative of 7cos(4x) ?
The derivative of 7cos(4x) is -28sin(4x)
What is the first derivative of 7cos(4x) ?
The first derivative of 7cos(4x) is -28sin(4x)