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Popular >

integral from 1 to 4 of x^2+2

Solution

\int_{1}^{4} x^{2} + 2 d x

Solution

27

Solution steps

\int_{1}^{4} x^{2} + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x + \int_{1}^{4} 2 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 2 d x = 6

= 21 + 6

Simplify

= 27

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tangent of (0.1666)(0.998)^x tangent of

(0.1666) (0.998)^{x}

derivative of (2x^2-5x+4/(sqrt(x)))

\frac{d}{d x} (\frac{2 x ^{2} - 5 x + 4}{x})

area y=sqrt(x+4),y= x/2+2 area

y = x + 4, y = \frac{x}{2} + 2

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of x^2+2 ?
The integral from 1 to 4 of x^2+2 is 27