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Popular >

xy^'+4y=2x^3

Solution

x y^{^{'}} + 4 y = 2 x^{3}

Solution

y = \frac{2 x ^{3}}{7} + \frac{c _{1}}{x ^{4}}

Solution steps

x y^{'} (x) + 4 y = 2 x^{3}

Solve linear ODE:

y = \frac{2 x ^{3}}{7} + \frac{c _{1}}{x ^{4}}

y = \frac{2 x ^{3}}{7} + \frac{c _{1}}{x ^{4}}

Popular Examples

tangent of y=sqrt(7x+2),(2,4)tangent of

y = 7 x + 2, (2, 4)

integral of e^{-16x}

\int e^{- 16 x} d x

derivative of 1-e^{-x}sin(y)

\frac{d}{d x} (1 - e^{- x} sin (y))

derivative of sqrt(x/(x^2+5))

\frac{d}{d x} (\frac{x}{x ^{2} + 5})

(\partial)/(\partial x)(1/(sqrt(x)))

\frac{\partial}{\partial x} (\frac{1}{x})

Frequently Asked Questions (FAQ)

What is the solution for xy^'+4y=2x^3 ?
The solution for xy^'+4y=2x^3 is y=(2x^3)/7+(c_{1})/(x^4)