What is the derivative of f(x)=4x^3+9 ?

The derivative of f(x)=4x^3+9 is 12x^2

What is the first derivative of f(x)=4x^3+9 ?

The first derivative of f(x)=4x^3+9 is 12x^2

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derivative of

f (x) = 4 x^{3} + 9

12 x^{2}

Solution steps

\frac{d}{d x} (4 x^{3} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (9)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (9) = 0

= 12 x^{2} + 0

Simplify

= 12 x^{2}

(- x^{- 2})^{^{'}}

(x^{2} + 2 x - 1) y^{^{'}} - (x + 1) y = x - 1

x \to 0 lim (x^{4} cos (\frac{5}{x}))

\int t^{2} (t^{3} - 4)^{2} d t

(x - 2)^{4} + e^{x - 2} + (x - 2 \cdot z)^{2}

What is the derivative of f(x)=4x^3+9 ?
The derivative of f(x)=4x^3+9 is 12x^2
What is the first derivative of f(x)=4x^3+9 ?
The first derivative of f(x)=4x^3+9 is 12x^2