What is the limit as x approaches-1 of ln(x+1) ?

The limit as x approaches-1 of ln(x+1) is Does not exist

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limit as x approaches-1 of ln(x+1)

x \to - 1 lim (ln (x + 1))

Does not exist

Solution steps

x \to - 1 lim (ln (x + 1))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (ln (x + 1)) = - \infty

x \to - 1 - lim (ln (x + 1)) =

Does not exist

= Does not exist

\frac{\partial}{\partial x} (\frac{1}{2} (x^{2} + 4 y^{2}))

\frac{\partial}{\partial x} (\frac{1}{2 x})

2 x y \frac{d y}{d x} = y^{2} - x^{2} + 1

100 x^{2} + 400 x + 5000, 0.5

\int e^{y (1 - x)} d x

What is the limit as x approaches-1 of ln(x+1) ?
The limit as x approaches-1 of ln(x+1) is Does not exist