What is (\partial)/(\partial x)(4xcos(4xy)) ?

The answer to (\partial)/(\partial x)(4xcos(4xy)) is 4(cos(4xy)-4xysin(4xy))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4xcos(4xy))

\frac{\partial}{\partial x} (4 x cos (4 x y))

4 (cos (4 x y) - 4 x y sin (4 x y))

Solution steps

\frac{\partial}{\partial x} (4 x cos (4 x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (x cos (4 x y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = cos (4 x y)

= 4 (\frac{\partial}{\partial x} (x) cos (4 x y) + \frac{\partial}{\partial x} (cos (4 x y)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (cos (4 x y)) = - sin (4 x y) \cdot 4 y

= 4 (1 \cdot cos (4 x y) + (- sin (4 x y) \cdot 4 y) x)

Simplify

= 4 (cos (4 x y) - 4 x y sin (4 x y))

x \to 0 lim (\frac{sin ( 20 x )}{x})

x \to 2 + lim (- \frac{1}{x ^{2} - 4})

\int (tan (θ) sec (θ)) d θ

\int \frac{1 - cos ( x )}{1 + cos ( x )} d x

\int e^{2 x - 7} d x

What is (\partial)/(\partial x)(4xcos(4xy)) ?
The answer to (\partial)/(\partial x)(4xcos(4xy)) is 4(cos(4xy)-4xysin(4xy))