What is the derivative of 2/(\sqrt[3]{x^2)} ?

The derivative of 2/(\sqrt[3]{x^2)} is -(4x)/(3(x^2)^{4/3)}

What is the first derivative of 2/(\sqrt[3]{x^2)} ?

The first derivative of 2/(\sqrt[3]{x^2)} is -(4x)/(3(x^2)^{4/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

- \frac{4 x}{3 ( x ^{2} ) ^{\frac{4}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x^{2})^{- \frac{1}{3}})

Apply the chain rule:

- \frac{1}{3 ( x ^{2} ) ^{\frac{4}{3}}} \frac{d}{d x} (x^{2})

= - \frac{1}{3 ( x ^{2} ) ^{\frac{4}{3}}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= 2 (- \frac{1}{3 ( x ^{2} ) ^{\frac{4}{3}}} \cdot 2 x)

Simplify

2 (- \frac{1}{3 ( x ^{2} ) ^{\frac{4}{3}}} \cdot 2 x) : - \frac{4 x}{3 ( x ^{2} ) ^{\frac{4}{3}}}

= - \frac{4 x}{3 ( x ^{2} ) ^{\frac{4}{3}}}

\frac{d}{d x} (\frac{4 csc ( x )}{5 ^{x}})

x \to \infty lim (\frac{n}{n !})

ln (49 sin^{2} (x))

y^{^{''}} + 10 y^{^{'}} + 27 y = 0

\frac{\partial}{\partial v} (v^{2})

What is the derivative of 2/(\sqrt[3]{x^2)} ?
The derivative of 2/(\sqrt[3]{x^2)} is -(4x)/(3(x^2)^{4/3)}
What is the first derivative of 2/(\sqrt[3]{x^2)} ?
The first derivative of 2/(\sqrt[3]{x^2)} is -(4x)/(3(x^2)^{4/3)}