What is the derivative of sqrt(3x+9) ?

The derivative of sqrt(3x+9) is 3/(2sqrt(3x+9))

What is the first derivative of sqrt(3x+9) ?

The first derivative of sqrt(3x+9) is 3/(2sqrt(3x+9))

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\frac{d}{d x} (3 x + 9)

\frac{3}{2 3 x + 9}

Solution steps

\frac{d}{d x} (3 x + 9)

Apply the chain rule:

\frac{1}{2 3 x + 9} \frac{d}{d x} (3 x + 9)

= \frac{1}{2 3 x + 9} \frac{d}{d x} (3 x + 9)

\frac{d}{d x} (3 x + 9) = 3

= \frac{1}{2 3 x + 9} \cdot 3

Simplify

\frac{1}{2 3 x + 9} \cdot 3 : \frac{3}{2 3 x + 9}

= \frac{3}{2 3 x + 9}

\int \frac{1 + cos ( x )}{1 - cos ( x )} d x

\frac{d}{d x} (arcsin (5 x))

\frac{3}{5} x^{\frac{5}{3}} - \frac{3}{4} x^{\frac{1}{3}} + 9

x \to - 2 + lim (\frac{1 - x}{x ^{3} + 8})

x \to 1 - lim (\frac{2}{x - 1})

What is the derivative of sqrt(3x+9) ?
The derivative of sqrt(3x+9) is 3/(2sqrt(3x+9))
What is the first derivative of sqrt(3x+9) ?
The first derivative of sqrt(3x+9) is 3/(2sqrt(3x+9))