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Popular >

xy^'+2y=8x^2

Solution

x y^{^{'}} + 2 y = 8 x^{2}

Solution

y = 2 x^{2} + \frac{c _{1}}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = 8 x^{2}

Solve linear ODE:

y = 2 x^{2} + \frac{c _{1}}{x ^{2}}

y = 2 x^{2} + \frac{c _{1}}{x ^{2}}

Popular Examples

3y^{''}+5y^'+2y=0

3 y^{^{''}} + 5 y^{^{'}} + 2 y = 0

integral of (3+2cos(x))^2

\int (3 + 2 cos (x))^{2} d x

limit as x approaches 2 of (6x)/(x-2)

x \to 2 lim (\frac{6 x}{x - 2})

tangent of f(x)=11sin(x),\at x=((3pi))/4 tangent of

f (x) = 11 sin (x), at x = \frac{( 3 π )}{4}

integral from 1 to 4 of ((2x+1))/(2x)

\int_{1}^{4} \frac{( 2 x + 1 )}{2 x} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+2y=8x^2 ?
The solution for xy^'+2y=8x^2 is y=2x^2+(c_{1})/(x^2)