What is the derivative of F(x)=(x^2)/(4+sqrt(x)) ?

The derivative of F(x)=(x^2)/(4+sqrt(x)) is (4x(4+sqrt(x))-x^{3/2})/(2(4+sqrt(x))^2)

What is the first derivative of F(x)=(x^2)/(4+sqrt(x)) ?

The first derivative of F(x)=(x^2)/(4+sqrt(x)) is (4x(4+sqrt(x))-x^{3/2})/(2(4+sqrt(x))^2)

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derivative of

F (x) = \frac{x ^{2}}{4 + x}

\frac{4 x ( 4 + x ) - x ^{\frac{3}{2}}}{2 ( 4 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{4 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 4 + x ) - \frac{d}{d x} ( 4 + x ) x ^{2}}{( 4 + x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 + x) = \frac{1}{2 x}

= \frac{2 x ( 4 + x ) - \frac{1}{2 x} x ^{2}}{( 4 + x ) ^{2}}

Simplify

\frac{2 x ( 4 + x ) - \frac{1}{2 x} x ^{2}}{( 4 + x ) ^{2}} : \frac{4 x ( 4 + x ) - x ^{\frac{3}{2}}}{2 ( 4 + x ) ^{2}}

= \frac{4 x ( 4 + x ) - x ^{\frac{3}{2}}}{2 ( 4 + x ) ^{2}}

\frac{d y}{d x} = y + y^{3}

\int_{- 9}^{4} ∣ x + 5 ∣ d x

\int \frac{x}{x ^{2} - 6 x + 8} d x

x^{^{'}} = x^{2}, x (0) = 1

n = 0 \sum \infty (\frac{1}{2})^{2 n + 1}

What is the derivative of F(x)=(x^2)/(4+sqrt(x)) ?
The derivative of F(x)=(x^2)/(4+sqrt(x)) is (4x(4+sqrt(x))-x^{3/2})/(2(4+sqrt(x))^2)
What is the first derivative of F(x)=(x^2)/(4+sqrt(x)) ?
The first derivative of F(x)=(x^2)/(4+sqrt(x)) is (4x(4+sqrt(x))-x^{3/2})/(2(4+sqrt(x))^2)