What is the sum from n=1 to infinity of 1/(2n+7) ?

The sum from n=1 to infinity of 1/(2n+7) is diverges

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sum from n=1 to infinity of 1/(2n+7)

n = 1 \sum \infty \frac{1}{2 n + 7}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{2 n + 7}

Apply Series Integral Test:

diverges

= diverges

\frac{1}{( s ^{2} + 4 ) ( s ^{2} + 2 s + 2 )}

2 t \cdot sin (t)

t y^{^{'}} - y = \frac{- t ^{3}}{y ^{2}}

7 x (\frac{d y}{d x}) = 2 x e^{x} - 7 y + 6 x^{2}

x \to 2 lim ((4 x - 3) (x^{2} + 5))

What is the sum from n=1 to infinity of 1/(2n+7) ?
The sum from n=1 to infinity of 1/(2n+7) is diverges