What is the derivative of (8-3x^2^3) ?

The derivative of (8-3x^2^3) is -18x(8-3x^2)^2

What is the first derivative of (8-3x^2^3) ?

The first derivative of (8-3x^2^3) is -18x(8-3x^2)^2

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\frac{d}{d x} ((8 - 3 x^{2})^{3})

- 18 x (8 - 3 x^{2})^{2}

Solution steps

\frac{d}{d x} ((8 - 3 x^{2})^{3})

Apply the chain rule:

3 (8 - 3 x^{2})^{2} \frac{d}{d x} (8 - 3 x^{2})

= 3 (8 - 3 x^{2})^{2} \frac{d}{d x} (8 - 3 x^{2})

\frac{d}{d x} (8 - 3 x^{2}) = - 6 x

= 3 (8 - 3 x^{2})^{2} (- 6 x)

Simplify

= - 18 x (8 - 3 x^{2})^{2}

y^{^{'}} = x ln (x), y (1) = 2

\int x (2 + x^{3})^{2} d x

\int I n^{2} d x

\int \frac{1 + cos ( x )}{cos ^{2} ( x )} d x

f (x) = 6 x^{2} - 6 x, at x = 0

What is the derivative of (8-3x^2^3) ?
The derivative of (8-3x^2^3) is -18x(8-3x^2)^2
What is the first derivative of (8-3x^2^3) ?
The first derivative of (8-3x^2^3) is -18x(8-3x^2)^2