What is the first derivative of 1+x^2 ?

The first derivative of 1+x^2 is 2x

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derivative of 1+x^2

derivative of

1 + x^{2}

2 x

Solution steps

\frac{d}{d x} (1 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

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