What is the derivative of-8cos(x) ?

The derivative of-8cos(x) is 8sin(x)

What is the first derivative of-8cos(x) ?

The first derivative of-8cos(x) is 8sin(x)

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\frac{d}{d x} (- 8 cos (x))

8 sin (x)

Solution steps

\frac{d}{d x} (- 8 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (cos (x))

Apply the common derivative:

\frac{d}{d x} (cos (x)) = - sin (x)

= - 8 (- sin (x))

Simplify

= 8 sin (x)

e^{x} x + 2 e^{x}

\int \frac{8 + x}{64 - x ^{2}} d x

\frac{d}{d x} (2 x (cos (x^{2})))

\frac{d}{d x} (x^{3} - 12 x + 2)

\int 4 + 8 cos (θ) + 4 cos^{2} (θ) d θ

What is the derivative of-8cos(x) ?
The derivative of-8cos(x) is 8sin(x)
What is the first derivative of-8cos(x) ?
The first derivative of-8cos(x) is 8sin(x)