What is the integral of xe^{2x+1} ?

The integral of xe^{2x+1} is 1/2 e^{2x+1}x-1/4 e^{2x+1}+C

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integral of xe^{2x+1}

\int x e^{2 x + 1} d x

\frac{1}{2} e^{2 x + 1} x - \frac{1}{4} e^{2 x + 1} + C

Solution steps

\int x e^{2 x + 1} d x

Apply Integration By Parts

: \frac{1}{2} e^{2 x + 1} x - \int \frac{1}{2} e^{2 x + 1} d x

= \frac{1}{2} e^{2 x + 1} x - \int \frac{1}{2} e^{2 x + 1} d x

\int \frac{1}{2} e^{2 x + 1} d x = \frac{1}{4} e^{2 x + 1}

= \frac{1}{2} e^{2 x + 1} x - \frac{1}{4} e^{2 x + 1}

Add a constant to the solution

= \frac{1}{2} e^{2 x + 1} x - \frac{1}{4} e^{2 x + 1} + C

x \to 0 lim (\frac{x}{x ^{2} - 6 x})

f (x) = \frac{5 x - 7}{x + 1}, at x = 0

\frac{d}{d x} (2 x + 3 x)

\frac{\partial}{\partial x} (6 e^{x y + 9})

f (x) = x^{2} - 2, at x = - 5

What is the integral of xe^{2x+1} ?
The integral of xe^{2x+1} is 1/2 e^{2x+1}x-1/4 e^{2x+1}+C