What is (\partial)/(\partial z)(x^2y+y^2z) ?

The answer to (\partial)/(\partial z)(x^2y+y^2z) is y^2

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(\partial)/(\partial z)(x^2y+y^2z)

\frac{\partial}{\partial z} (x^{2} y + y^{2} z)

y^{2}

Solution steps

\frac{\partial}{\partial z} (x^{2} y + y^{2} z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x^{2} y) + \frac{\partial}{\partial z} (y^{2} z)

\frac{\partial}{\partial z} (x^{2} y) = 0

\frac{\partial}{\partial z} (y^{2} z) = y^{2}

= 0 + y^{2}

Simplify

= y^{2}

n = 1 \sum \infty \frac{n}{n ( n + 3 )}

\frac{\partial}{\partial x} (4 e^{x - y})

\frac{d y}{d x} = e^{2.3 x - 1.9 y}

\int sec^{4} (\frac{3 x}{2}) tan^{2} (\frac{3 x}{2}) d x

- \frac{e ^{- s}}{( ( s ^{2} + 4 ) \cdot s ^{2} )}

What is (\partial)/(\partial z)(x^2y+y^2z) ?
The answer to (\partial)/(\partial z)(x^2y+y^2z) is y^2